Data
A 5 MW turbine rotor diameter is 126m ( from the Repower website http://www.repower.de/index.php?id=12&L=1 )
According to Martin Alder, a wind farm owner and developer:
Across wind turbine spacing = 3 x dia (Assume tower to tower)
Down wind turbine spacing = 5 x dia
According to Colin Palmer, of Wind Prospect, a leading wind farm developer, load factors of 30 – 35% onshore, and 40% offshore are readilly achievalbe.
So assume 33%.
Calculation
Take a 70 mile by 70 mile square. This equals 112 km by 112 km
So downwind, turbine spacing (tower to tower) will be 126 x 3 = 378m. Thus in 70 miles / 112 km we can accommodate (112 x 1000 / 378 ) +1 = 297.3 towers (allowing half blade length to protrude out of area at edges).
Similarly, cross wind, we need 5 x 126 = 630 m. Thus in 70 miles / 112 km we can accommodate (112 x 1000 /630) +1 = 178.8 towers (again allowing half blade length to protrude out of area at edges).
Thus a 70 mile by 70 mile square can accommodate 297.3 x 178.8 = 53,157 turbines..
At 5 MW each, these will generate at peak 265.7 GW.
Assuming reasonable sites and a 1/3 , 33% load factor, this will generate on average 79.73 GW.
